In the 2022 AMC 10A competition, Problem #18 investigates composite transformations in the Cartesian plane using rotations and reflections:
Contest Problem Statement: "Let $T_k$ be the transformation of the coordinate plane that first rotates the plane $k$ degrees counterclockwise around the origin and then reflects the plane across the $y$-axis. What is the least positive integer $n$ such that performing the sequence of transformations $T_1, T_2, T_3, \dots, T_n$ returns the point $(1, 0)$ back to itself?"
Understanding the Transformation $T_k$
Let a point have polar angle $\theta$. What does $T_k$ do?
Counterclockwise rotation by $k^\circ$: Adds $k^\circ$ to the angle:
$$\theta \mapsto \theta + k^\circ$$
Reflection across the $y$-axis: A reflection across the vertical $y$-axis replaces $x$ with $-x$. In terms of polar angle, $(x, y) = (\cos\phi, \sin\phi)$ becomes $(-\cos\phi, \sin\phi) = (\cos(180^\circ - \phi), \sin(180^\circ - \phi))$:
$$\phi \mapsto 180^\circ - \phi$$
Combining both operations, $T_k$ transforms any angle $\theta$ into:
For $\theta_{2m} \equiv 0^\circ \pmod{360^\circ}$, we need $m = 360 \implies n = 720$.
For an odd number of steps $n = 2m + 1$:
$$\theta_{2m + 1} = 180^\circ - (m + 1)^\circ$$
For $\theta_{2m + 1} \equiv 0^\circ \pmod{360^\circ}$, we need $m + 1 = 180 \implies m = 179$!
Thus $n = 2(179) + 1 = 359$.
Because $359 < 720$, the least positive integer $n$ is 359!
In this lesson, we write a simulation in Lua using dcos() and dsin() to verify this coordinate orbit.
rx = x * dcos(k) - y * dsin(k) ry = x * dsin(k) + y * dcos(k) x = -rx; y = ry if math.abs(x - 1) < 1e-6 and math.abs(y) < 1e-6 then break end
Move the mouse over a dotted box for more information.
The simulation demonstrates that rotation combined with reflection creates an alternating parity pattern, returning $(1, 0)$ to itself at step 359.
Now you try.
Replace ???? with -x_rot and click Run to find the period = 359$. Then check Example 1 to see points plotted on the canvas! on the canvas screen!
Type your code here:
See your results here:
The code has ???? for the y-axis reflection. Replace ???? with -x_rot and click Run to find the minimum number of steps to return to
Notice that at $n = 359$, $(x, y) = (1.0000, 0.0000)$.
This confirms the contest answer: (A) 359.
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